Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - 6.5 Graphs of the Tangent and Cotangent Functions - 6.5 Exercises - Page 623: 26

Answer

see graph.

Work Step by Step

For $y=tan(\frac{x}{2}+\pi)=tan[\frac{1}{2}(x+2\pi)]$, we can identify its period as $p=\frac{\pi}{1/2}=2\pi$, phase shift as $2\pi$ to the left, see graph.
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