Answer
see graph.
Work Step by Step
For $y=tan(2x-\pi)=tan[2(x-\frac{\pi}{2})]$, we can identify its period as $p=\frac{\pi}{2}$, phase shift as $\frac{\pi}{2}$ tot he right, see graph.
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 6 - The Circular Functions and Their Graphs - 6.5 Graphs of the Tangent and Cotangent Functions - 6.5 Exercises - Page 623: 25
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