Answer
(a) $\frac{2\pi}{5}\ rad$
(b) $12\pi\ cm$
(c) $3\pi\ cm/sec$
Work Step by Step
Given $r=30\ cm, \omega=\frac{\pi}{10}\ rad/sec, t=4\ sec$, we have:
(a) the angle generated by P in time t is $\theta=\omega t=\frac{\pi}{10}\times4=\frac{2\pi}{5}\ rad$
(b) the distance traveled by P along the circle in time t is $s=r\theta=12\pi\ cm$
(c) the linear speed of P is $v=\omega r=\frac{\pi}{10}\times30=3\pi\ cm/sec$
