Answer
$\frac{4\pi}{3}, \frac{5\pi}{3}$
Work Step by Step
Given $sin(s)=-\frac{\sqrt 3}{2}$, we can find a reference angle as $s_0=sin^{-1}(\frac{\sqrt 3}{2})=\frac{\pi}{3}$. In $[0,2\pi)$, there are two angles $s=\pi+\frac{\pi}{3}, 2\pi-\frac{\pi}{3}$ or $s=\frac{4\pi}{3}, \frac{5\pi}{3}$
