Answer
$\color{blue}{\csc{(\frac{13\pi}{3})}=\frac{2\sqrt3}{3}}$
Work Step by Step
Note that $\dfrac{13\pi}{3}$ is coterminal with:
$\dfrac{13\pi}{3} - 4\pi=\dfrac{13\pi}{3} - \dfrac{12\pi}{3}=\dfrac{\pi}{3}$
Figure 13 on page 579 of this book shows that the unit circle point $(\frac{1}{2}, \frac{\sqrt3}{2})$ corresponds to the real number $\dfrac{13\pi}{3}$ or $\dfrac{\pi}{3}$.
RECALL:
(i) $\cos{s} = x$
(ii) $\sin{s} = y$
(iii) $\tan{s}=\dfrac{y}{x}$
(iv) $\sec{s} =\dfrac{1}{x}$
(v) $\csc{s} = \dfrac{1}{y}$
(vi) $\cot{s} = \dfrac{x}{y}$
Use the coordinates of the unit circle point above and the formula in (v) above to obtain:
$\color{blue}{\csc{(\frac{13\pi}{3})}=\csc{\frac{\pi}{3}}=\dfrac{1}{\frac{\sqrt3}{2}}=1 \cdot \frac{2}{\sqrt3}=\frac{2}{\sqrt3}=\frac{2\sqrt3}{(\sqrt3)(\sqrt3)}=\frac{2\sqrt3}{3}}$