Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - Test - Page 562: 10

Answer

See graph and explanations.

Work Step by Step

1. Graph the line $3x-4y=0, x\leq0$ (red) as shown, with angle $\theta$ also shown in the figure. 2. We can find a point on the line as $(-4,-3)$ 3. We have $sin\theta=\frac{-3}{\sqrt {(-4)^2+(-3)^2}}=-\frac{3}{5}$ 4. We have $cos\theta=-\frac{4}{5}$ 5. We have $tan\theta=\frac{3}{4}$ 6. We have $cot\theta=\frac{4}{3}$ 7. We have $sec\theta=\frac{1}{cos\theta}=-\frac{5}{4}$ 8. We have $csc\theta=\frac{1}{sin\theta}=-\frac{5}{3}$
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