Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - Test - Page 562: 1

Answer

$23^\circ$, $113^\circ$.

Work Step by Step

By definition, the complement angle of $67^\circ$ is $90^\circ-67^\circ=23^\circ$ and the supplement angle of $67^\circ$ is $180^\circ-67^\circ=113^\circ$.
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