Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.4 Solutions and Applications off Right Triangles - 5.4 Exercises - Page 548: 46

Answer

$469\ m$

Work Step by Step

Use the figure, we have $A=90^\circ-32^\circ30'=57^\circ30', b=252\ m$, thus $c=\frac{b}{cosA}=\frac{252}{cos57^\circ30'}\approx469\ m$
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