Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.4 Solutions and Applications off Right Triangles - 5.4 Exercises - Page 548: 41

Answer

$128\ ft$

Work Step by Step

Use the figure and numbers given in the exercise, assume the horizontal gap is $x\ ft$, we have $tan20^\circ=\frac{30}{x}$ and $tan50^\circ=\frac{H-30}{x}$, where $H$ is the height of the right building. Thus we have $\frac{30}{tan20^\circ}=\frac{H-30}{tan50^\circ}$ and $H=30+\frac{30tan50^\circ}{tan20^\circ}\approx128\ ft$
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