Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter P - Section P.8 - Modeling with Equations - Exercise Set - Page 124: 48

Answer

Passenger train $60$ miles per hour; freight train $40$ miles per hour.

Work Step by Step

Step 1. Assume the average velocity of the passenger train is $x$ miles per hour; then the average velocity of the freight train is $x-20$ miles per hour. Step 2. For the same time $t$, we have $t=\frac{240}{x}=\frac{160}{x-20}$, which gives $\frac{3}{x}=\frac{2}{x-20}$. Step 3. Cross multiply for the above equation to get $3x-60=2x$. Thus we have $x=60\ mph$ and $x-20=40\ mph$.
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