Answer
The expression has no real solutions.
Work Step by Step
The expression provided is:
$\begin{align}
& {{x}^{2}}=2x-19 \\
& {{x}^{2}}-2x+19=0
\end{align}$
Use the following expression,
$D={{b}^{2}}-4ac$
Substitute the values in the expression,
$\begin{align}
& a=1 \\
& b=-2 \\
& c=19
\end{align}$
Now, solve the expression
$\begin{align}
& D={{b}^{2}}-4ac \\
& ={{\left( -2 \right)}^{2}}-4\left( 1 \right)\left( 19 \right) \\
& =4-76 \\
& =-72
\end{align}$
As, $D<0$
Therefore, the equation has no real solutions.
