Answer
$\{2\}$
Work Step by Step
Step 1. Isolate the radical to get $\sqrt {2x-3}=3-x$
Step 2. Take the square on both sides to get $2x-3=x^2-6x+9$, $x^2-8x+12=0$ and $(x-2)(x-6)=0$
Step 3. Test the solutions $x=2,6$ in the original equation. We should discard $x=6$ and keep $x=2$ as the answer.
