Answer
$\frac{x^2}{100}+\frac{y^2}{51}=1$
Work Step by Step
Step 1. With the given conditions, we have
$c=\frac{7+7}{2}=7, a=\frac{10+10}{2}=10, b=\sqrt {10^2-7^2}=\sqrt {51}$
Step 2. We can write the equation as $\frac{x^2}{100}+\frac{y^2}{51}=1$
