Answer
$(y+1)^2=x$
Work Step by Step
Step 1. From the given conditions, we have $y=t-1$ which gives $t=y+1$. Using it in the first equation, we have $x=(y+1)^2$ or $(y+1)^2=x$
Step 2. We can graph the parabola as shown in the figure and it opens to the right.
