Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.6 - Conic Sections in Polar Coordinates - Exercise Set - Page 1032: 52

Answer

$r=\frac{3}{2-3 cos\theta}$

Work Step by Step

Given a hyperbola ($e=\frac{3}{2}$) with focus at the pole and directrix as $x=-1$, we have $p=1$ on the left side of the pole, and we can write the equation as: $r=\frac{ep}{1-e\ cos\theta}=\frac{\frac{3}{2}(1)}{1-\frac{3}{2} cos\theta}$ or $r=\frac{3}{2-3 cos\theta}$
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