Answer
See graph and explanations.
Work Step by Step
Step 1. Rewrite the equation as $y^2+(4x)y+(x^2-3)$ and let $a=1, b=4x, c=x^2-3$
Step 2. Use the quadratic formula $y=\frac{-b\pm\sqrt {b^2-4ac}}{2a}$ to get $y=\frac{-4x\pm\sqrt {(4x)^2-4(1)(x^2-3)}}{2}=-2x\pm\sqrt {3x^2+3}$
Step 3. We can graph the equations $y_1=-2x+\sqrt {3x^2+3}$ and $y_2=-2x-\sqrt {3x^2+3}$ as shown in the figure.
