Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.2 - The Hyperbola - Exercise Set - Page 984: 98

Answer

$(y+1)^2=-12(x-2)$

Work Step by Step

Rewrite the equation as: $(y^2+2y+1)=-12x+23+1$ We have: $(y+1)^2=-12(x-2)$
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