Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Section 9.2 - The Hyperbola - Exercise Set - Page 984: 89

Answer

See explanations.

Work Step by Step

From $c^2=a^2+b^2$, dividing both sides by $a^2$, we have $\frac{c^2}{a^2}=1+\frac{b^2}{a^2}$. When $\frac{c}{a}\to\infty$, we have $\frac{b}{a}\to\infty$. Thus the slope of the asymptote will be $\frac{b}{a}\to\infty$, indicating nearly vertical asymptotes and hyperbola branches.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.