Answer
$(0, -5)$, $(0, 5)$, $(0, -\sqrt {34})$, $(0, \sqrt {34})$.
Work Step by Step
From the given equation, we have $a^2=25, b^2=9$; thus $c=\sqrt {a^2+b^2}=\sqrt {34}$ with a vertical transverse axis. The vertices of the equation can be found at $(0, -5)$ and $(0, 5)$. The foci are located at $(0, -\sqrt {34})$ and $(0, \sqrt {34})$.
