Answer
$(-5, 0)$, $(5,0)$, $(-\sqrt {34},0)$, $(\sqrt {34},0)$
Work Step by Step
From the given equation, we have $a^2=25, b^2=9$; thus $c=\sqrt {a^2+b^2}=\sqrt {34}$. The vertices of the equation can be found at $(-5, 0)$ and $(5,0)$. The foci are located at $(-\sqrt {34},0)$ and $(\sqrt {34},0)$
