Answer
$(y+1)^2=x$; see figure.
Work Step by Step
Step 1. Using the second equation, we have $y=t-1$ or $t=y+1$
Step 2. Substituting into the first equation, we have $x=(y+1)^2$ or $(y+1)^2=x$
Step 3. Given $-1\leq t\leq 3$, we have $-2\leq y\leq 2$ and $0\leq x\leq 9$.
We can graph the above equation as shown in the figure.
