Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 9 - Review Exercises - Page 1036: 35

Answer

$x^2=-44y$

Work Step by Step

Step 1. Based on the given conditions, we have $2p=-11-(11)=-22$ and $p=-11$ and the parabola opens downwards. Step 2. The vertex is at $(0,\frac{11-11}{2})$ or $(0,0)$ and we can write the equation as $x^2=4(-11)y=-44y$
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