Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 8 - Section 8.1 - Matrix Solutions to Linear Systems - Exercise Set - Page 893: 16

Answer

The new matrix is, $\left[ \begin{matrix} 1 & -1 & 5 & -6 \\ 0 & 6 & -16 & -8 \\ 1 & 3 & 2 & 5 \\ \end{matrix} \right]$

Work Step by Step

Consider the provided matrix, $\left[ \begin{matrix} 1 & -1 & 5 & -6 \\ 3 & 3 & -1 & 10 \\ 1 & 3 & 2 & 5 \\ \end{matrix} \right]$ The operation $-3{{R}_{1}}+{{R}_{2}}$ implies that each element of the first row will be multiplied by $-3$ and then added with the corresponding element of the second row. The new matrix is obtained after performing the row operation ${{R}_{2}}\to -3{{R}_{1}}+{{R}_{2}}$ $\left[ \begin{matrix} 1 & -1 & 5 & -6 \\ -3+3 & 3+3 & -15-1 & -18+10 \\ 1 & 3 & 2 & 5 \\ \end{matrix} \right]=\left[ \begin{matrix} 1 & -1 & 5 & -6 \\ 0 & 6 & -16 & -8 \\ 1 & 3 & 2 & 5 \\ \end{matrix} \right]$ Therefore, the new matrix is $\left[ \begin{matrix} 1 & -1 & 5 & -6 \\ 0 & 6 & -16 & -8 \\ 1 & 3 & 2 & 5 \\ \end{matrix} \right]$
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