Answer
$(3,0)$, $(\dfrac{-9}{5}, \dfrac{12}{5})$
Work Step by Step
Re-arrange the given equations to get
$x=-2y+3 $
and $(-2y+3)^2 +y^2=9$
$ \implies 4y^2-12y+9+y^2=9$
$ \implies y(5y-12) =0$
when $y=\dfrac{12}{5}$ then we have $x=\dfrac{-9}{5}$
when $y=0$ then we have $x=-2(0)+3=3$
Hence, our answers are: $(3,0)$, $(\dfrac{-9}{5}, \dfrac{12}{5})$
