Answer
$(-2,-1)$, $(-2, 1)$, $(2,-1)$, $(2,1)$
Work Step by Step
Re-arrange the given equations to get
$4x^2-2y^2=14$
Adding the equations, we get $(3x^2+2y^2)^2 +(4x^2-2y^2)=14+14$
$ \implies 7x^2=28$
This gives: $ x^2 =4 \implies x=2,-2$
when $ x^2 =4 \implies 2(4)-y^2=7$ gives: $y^2=1 \implies y=1,-1$
Hence, our answers are: $(-2,-1)$, $(-2, 1)$, $(2,-1)$, $(2,1)$
