Answer
Step 1. See figure.
Step 2. $\sqrt {29}$
Work Step by Step
Step 1. Given $\vec v=5i-2j$, we can sketch the vector as shown in the figure.
Step 2. We can find the magnitude of the vector as $|\vec v|=\sqrt {(5)^2+(-2)^2}=\sqrt {29}$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 6 - Section 6.7 - The Dot Product - Exercise Set - Page 799: 83
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