Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.6 - Vectors - Exercise Set - Page 785: 119

Answer

The obtuse angle $\theta $ is $137.72{}^\circ $.

Work Step by Step

The magnitude of $\mathbf{v}$ is $\begin{align} & \left\| \mathbf{v} \right\|=\sqrt{{{3}^{2}}+{{\left( -2 \right)}^{2}}} \\ & =\sqrt{9+4} \\ & =\sqrt{13} \end{align}$ The magnitude of $\mathbf{w}$ is $\begin{align} & \left\| \mathbf{w} \right\|=\sqrt{{{\left( -1 \right)}^{2}}+{{\left( 4 \right)}^{2}}} \\ & =\sqrt{1+16} \\ & =\sqrt{17} \end{align}$ The value of $\theta $ is $\begin{align} & \cos \theta =\frac{3\left( -1 \right)+\left( -2 \right)\left( 4 \right)}{\left\| \mathbf{v} \right\|\left\| \mathbf{w} \right\|} \\ & \cos \theta =\frac{3\left( -1 \right)+\left( -2 \right)\left( 4 \right)}{\sqrt{13}\times \sqrt{17}} \\ & \cos \theta =-0.74 \\ & \theta =137.72{}^\circ \end{align}$
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