Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.6 - Vectors - Exercise Set - Page 782: 51

Answer

$\mathbf{v}=-0.20\mathbf{i}+0.46\mathbf{j}$

Work Step by Step

Therefore, $\begin{align} & \mathbf{v}=\frac{1}{2}\cos {{113}^{\circ }}\mathbf{i}+\frac{1}{2}\sin {{113}^{\circ }}\mathbf{j} \\ & =\left[ \frac{1}{2}\times \left( -0.39 \right) \right]\mathbf{i}+\left[ \frac{1}{2}\times \left( 0.92 \right) \right]\mathbf{j} \\ & =-0.20\mathbf{i}+0.46\mathbf{j} \end{align}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.