Answer
$\frac{1}{\sqrt{2}}\mathbf{i}+\frac{1}{\sqrt{2}}\mathbf{j}$
Work Step by Step
Therefore,
$\begin{align}
& \left\| \mathbf{v} \right\|=\sqrt{{{1}^{2}}+{{1}^{2}}} \\
& =\sqrt{2}
\end{align}$
So,
$\frac{\mathbf{v}}{\parallel \mathbf{v}\parallel }=\frac{1}{\sqrt{2}}\mathbf{i}+\frac{1}{\sqrt{2}}\mathbf{j}$
