Answer
$ -3, -\frac{1}{2}, 1$
Work Step by Step
Step 1. Given that $-3$ is a zero of $f(x)=2x^3+5x^2-4x-3$, we can use synthetic division to get the quotient as shown in the figure.
Step 2. We have $(x+3)(2x^2-x-1)=0$ or $(x+3)(2x+1)(x-1)=0$
Step 3. We can find the zeros as $x=-3, -\frac{1}{2}, 1$
