Answer
$(x+3)^2+y^2=9$
$C(-3,0)$, $r=3$
See graph.
Work Step by Step
Step 1. Rewrite the equation of the circle as
$x^2+6x+9 +y^2=9$ or $(x+3)^2+y^2=9$
Step 2. We can identify the center as $C(-3,0)$ and radius as $r=3$
Step 3. See graph.
