Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.2 - The Law of Cosines - Exercise Set - Page 730: 37

Answer

$157^\circ$, efficient walker.

Work Step by Step

Step 1. Using the given figure, we can identify the three sides as $5.78,3.0,2.9\ ft$ Step 2. The pace angle $\theta$ faces the longest side and using the Law of Cosines, we have $5.78^2=3.0^2+2.9^2-2(3.0)(2.9)cos\theta$ and $cos\theta\approx-0.9194$ Thus $\theta=acos(-0.9194)\approx157^\circ$ Step 3. The pace angle is large and close to $180^\circ$m, indicating that this dinosaur was an efficient walker without wasting its pace sideways.
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