Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.1 - The Law of Sines - Exercise Set - Page 722: 57

Answer

a. $493.8\ ft$ b. $343.0\ ft$

Work Step by Step

a. Step 1. Based on the given conditions, we can identify angle $\angle ABC=180^\circ-44^\circ=136^\circ$; thus angle $C=180^\circ-37^\circ-136^\circ=7^\circ$ Step 2. Using the Law of Sines, we have $\frac{sin37^\circ}{a}=\frac{sin7^\circ}{100}$; thus $a=\frac{100sin37^\circ}{sin7^\circ}\approx493.8\ ft$ b. Using the right triangle given in the figure of the exercise, we have $sin44^\circ=\frac{h}{a}$; thus $h=493.8sin44^\circ\approx343.0\ ft$
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