Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.1 - The Law of Sines - Exercise Set - Page 722: 54

Answer

The length of the pier is $\text{81}\text{.0 feet}$.

Work Step by Step

We will find B by observing the given figure. Using the linear pair of angles: $\begin{align} & B+85{}^\circ =180{}^\circ \\ & B=180{}^\circ -85{}^\circ \\ & B=95{}^\circ \end{align}$ Now, we will find angle C. Using the angle sum property of the triangle we get, $\begin{align} & A+B+C=180{}^\circ \\ & 37{}^\circ +95{}^\circ +C=180{}^\circ \\ & C=180{}^\circ -132{}^\circ \\ & C=48{}^\circ \end{align}$ Using the law of sines we will find a: $\begin{align} & \frac{a}{\sin A}=\frac{c}{\sin C} \\ & \frac{a}{\sin 37{}^\circ }=\frac{100}{\sin 48{}^\circ } \\ & a=\frac{100\sin 37{}^\circ }{\sin 48{}^\circ } \\ & \approx 81.0 \end{align}$ Therefore, the length of the pier is $\text{81}\text{.0 feet}$.
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