Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 6 - Section 6.1 - The Law of Sines - Exercise Set - Page 721: 50

Answer

The distance between A and B is about $264.4\text{ yards}$

Work Step by Step

Let us suppose c to be the distance from A to B. Now to find the angle B we will use the sum of angles property. $B=180{}^\circ -62{}^\circ -53{}^\circ =65{}^\circ $ Using the law of sines we will find c. $\begin{align} & \frac{c}{\sin C}=\frac{b}{\sin B} \\ & \frac{c}{\sin 53{}^\circ }=\frac{300}{\sin 65{}^\circ } \\ & c=\frac{300\sin 53{}^\circ }{\sin 65{}^\circ } \\ & \approx 264.4 \end{align}$ Therefore, the distance between A and B is about $264.4\text{ yards}$.
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