Answer
See explanations.
Work Step by Step
Step 1. $LHS=cos\theta cos(\frac{\pi}{2})-sin\theta sin(\frac{\pi}{2})=0-sin\theta=-sin\theta$
Step 2. $RHS=-sin\theta$
Step 3. Since $LHS=RHS$, we verified the identity.
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 5 - Test - Page 709: 9
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