Answer
The required solution is $\frac{\sqrt{3}}{2},\frac{1}{2},\frac{1}{2},\frac{\sqrt{3}}{2},0,1$
Work Step by Step
By putting the values according to the trigonometric functions, we get:
$\cos {{30}^{\circ }}=\frac{\sqrt{3}}{2}$
$\sin {{30}^{\circ }}=\frac{1}{2}$
$\cos {{60}^{\circ }}=\frac{1}{2}$
$\sin {{60}^{^{\circ }}}=\frac{\sqrt{3}}{2}$
$\cos {{90}^{\circ }}=0$
$\sin {{90}^{\circ }}=1$
