Answer
$260$ feet
Work Step by Step
Since, $\tan \theta= \dfrac{height}{Adjacent}$
We have the angle of elevation $\theta= 90^{\circ}$
height $=800$ feet
$ d $ is the distance.
Now, $ d=800 \times \tan (90^{\circ}) - 72^{\circ}$
or, $ d=260$ feet
