Answer
$257$
Work Step by Step
Here, we have $ \dfrac{x}{ \tan 40^{\circ}} = \dfrac{x}{ \tan 20^{\circ}}-400$
or, $ x= \dfrac{400}{\dfrac{1}{\tan 20^{\circ}}-\dfrac{1}{\tan 40}} $
or, $ x= \dfrac{400}{2.7475-1.1918} $
Simplify the above equation:
so, $ x=257$
