Answer
$\sqrt {35}$
Work Step by Step
Since, $\sec^2 \theta=1+\tan^2 \theta $
$\implies \tan \theta=\sqrt {1+\dfrac{1}{\cos^2 \theta}}$
or, $36=1+a^2 \implies a=\sqrt {35}$
Thus, $\cos (\dfrac{\pi}{2}- \theta)=\tan \theta=\sqrt {35}$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 4 - Mid-Chapter Check Point - Page 577: 15
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