Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 4 - Mid-Chapter Check Point - Page 577: 1

Answer

$\dfrac{\pi}{18} \text{ radians}$

Work Step by Step

Multiply $\dfrac{\pi \text{ radians}}{180^o}$ to the given angle measure to obtain: $=10 \cdot \dfrac{\pi \text{ radians}}{180^o} \\=\dfrac{\pi}{18} \text{ radians}$
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