Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.5 - Exponential Growth and Decay; Modeling Data - Exercise Set - Page 508: 58

Answer

$ y=1000e^{x\ln 7.3}$, $ y=1000e^{1.988x}$

Work Step by Step

$ y=ab^{x}$ is equivalent to $ y=ae^{x\ln b}$ $ y=1000(7.3)^{x}$ is equivalent to $ y=1000e^{x\ln 7.3}$ With $\ln 7.3\approx 1.988,$ $ y=1000e^{1.988x}$
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