Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.5 - Exponential Growth and Decay; Modeling Data - Exercise Set - Page 508: 57

Answer

$ y=100e^{x\ln 4.6}$, $ y=100e^{1.526x}$

Work Step by Step

$ y=ab^{x}$ is equivalent to $ y=ae^{x\ln b}$ $ y=100(4.6)^{x}$ is equivalent to $ y=100e^{x\ln 4.6}$ With $\ln 4.6\approx 1.526,$ $ y=100e^{1.526x}$
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