Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Section 3.4 - Exponential and Logarithmic Equations - Exercise Set - Page 488: 31

Answer

Solution set = $\displaystyle \{\frac{\ln 659}{5}\}.$ $ x\approx 1.30$

Work Step by Step

$ 3e^{5x}=1977\qquad $... divide with 3 $ e^{5x}=659$ $\qquad $... apply ln( ) to both sides, (use: $\ln e^{M}=M $) $\ln e^{5x}=\ln 659$ $ 5x=\ln 659\qquad $... divide with $5$ $ x=\displaystyle \frac{\ln 659}{5}\qquad $... round to 2 decimal places $ x\approx 1.30$
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