Answer
$0$
Work Step by Step
RECALL:
$y=\ln{x} \longrightarrow e^y=x.$
Note that $1 = e^0$.
Thus, the given expression can be written as
$\log{e^0}.$
Let $y=\ln{e^0}.$
Use the rule above to obtain
$y=\ln{e^0} \longrightarrow e^y=e^0.$
Use the rule "If $a^x=a^y$, then $x=y$" to obtain
$y=0.$
Therefore, $\ln{1}= \ln{e^0} = 0.$
