Answer
$\dfrac{1}{64}$
Work Step by Step
RECALL:
$\log_b{x}=y \longrightarrow b^y=x.$
Use the rule above to write the given equation in exponential form, then solve the equation to obtain
$\begin{array}{ccc}
&4^{-3} &= &x
\\&\frac{1}{4^3} &= &x
\\&\frac{1}{64} &= &x
\end{array}.$
Thus, $x=\dfrac{1}{64}$.
