Answer
$\dfrac{1}{2}$
Work Step by Step
RECALL:
$\log_b{b^x} = x.$
Note that
$9=\sqrt{81} = 81^{\frac{1}{2}}.$
Thus, the given expression can be written as
$\log_{81}{81^{\frac{1}{2}}}.$
Use the rule above to obtain:
$\dfrac{1}{2}.$
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 3 - Section 3.2 - Exponential Functions - Exercise Set - Page 463: 34
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