Answer
$\log_{15}{x}=2$
Work Step by Step
RECALL:
$b^y=x \longleftrightarrow \log_b{x} =y .$
Use the definition above to obtain
$15^{2} = x \longrightarrow \log_{15}{x}=2.$
Thus, the equivalent logarithmic form of the given expression is
$\log_{15}{x}=2.$
