Answer
$$\log_7 \left ( \frac{x^8}{\sqrt[3]{y}} \right )$$
Work Step by Step
We simplify as follows:
$$8\log_7x-\frac{1}{3}\log_7y=\log_7x^8- \log_7y^{\frac{1}{3}}=\log_7 \left ( \frac{x^8}{\sqrt[3]{y}} \right )$$
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