Precalculus (6th Edition) Blitzer

Published by Pearson
ISBN 10: 0-13446-914-3
ISBN 13: 978-0-13446-914-0

Chapter 3 - Mid-Chapter Check Point - Page 477: 23

Answer

$$\log_7 \left ( \frac{x^8}{\sqrt[3]{y}} \right )$$

Work Step by Step

We simplify as follows: $$8\log_7x-\frac{1}{3}\log_7y=\log_7x^8- \log_7y^{\frac{1}{3}}=\log_7 \left ( \frac{x^8}{\sqrt[3]{y}} \right )$$
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