Answer
$$\text{undefined}$$
Work Step by Step
We simplify as follows:
$$\log_3 (\log_2 \frac{1}{8})=\log_3 (\log_22^{-3})=\log_3(-3\log_22)=\log_3(-3(1))=\log_3-3=\text{ undefined }$$(since the logarithm is not defined for negative real numbers).
Precalculus (6th Edition) Blitzer
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13446-914-3
ISBN 13:
978-0-13446-914-0
Chapter 3 - Mid-Chapter Check Point - Page 477: 15
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